20 research outputs found

    Groups With Two Generators Having Unsolvable Word Problem And Presentations of Mihailova Subgroups

    Get PDF
    A presentation of a group with two generators having unsolvable word problem and an explicit countable presentation of Mihailova subgroup of F_2×F_2 with finite number of generators are given. Where Mihailova subgroup of F_2×F_2 enjoys the unsolvable subgroup membership problem.One then can use the presentation to create entities\u27 private key in a public key cryptsystem

    A recursive presentation for Mihailova's subgroup

    Get PDF
    We give an explicit recursive presentation for Mihailova's subgroup M(H)M(H) of Fn×FnF_n \times F_n corresponding to a finite, concise and Peiffer aspherical presentation H=H=. This partially answers a question of R.I. Grigorchuk, [8, Problem 4.14]. As a corollary, we construct a finitely generated recursively presented orbit undecidable subgroup of Aut(F3)Aut(F_3).Comment: 9 page

    Orbit decidability and the conjugacy problem for some extensions of groups

    No full text
    Given a short exact sequence of groups with certain conditions, 1 ? F ? G ? H ? 1, weprove that G has solvable conjugacy problem if and only if the corresponding action subgroupA 6 Aut(F) is orbit decidable. From this, we deduce that the conjugacy problem is solvable,among others, for all groups of the form Z2?Fm, F2?Fm, Fn?Z, and Zn?A Fm with virtually solvable action group A 6 GLn(Z). Also, we give an easy way of constructing groups of the form Z4?Fn and F3?Fn with unsolvable conjugacy problem. On the way, we solve the twisted conjugacy problem for virtually surface and virtually polycyclic groups, and give an example of a group with solvable conjugacy problem but unsolvable twisted conjugacy problem. As an application, an alternative solution to the conjugacy problem in Aut(F2) is given

    Orbit decidability and the conjugacy problem for some extensions of groups

    Full text link
    Given a short exact sequence of groups with certain conditions, 1FGH11\to F\to G\to H\to 1, we prove that GG has solvable conjugacy problem if and only if the corresponding action subgroup AAut(F)A\leqslant Aut(F) is orbit decidable. From this, we deduce that the conjugacy problem is solvable, among others, for all groups of the form Z2Fm\mathbb{Z}^2\rtimes F_m, F2FmF_2\rtimes F_m, FnZF_n \rtimes \mathbb{Z}, and ZnAFm\mathbb{Z}^n \rtimes_A F_m with virtually solvable action group AGLn(Z)A\leqslant GL_n(\mathbb{Z}). Also, we give an easy way of constructing groups of the form Z4Fn\mathbb{Z}^4\rtimes F_n and F3FnF_3\rtimes F_n with unsolvable conjugacy problem. On the way, we solve the twisted conjugacy problem for virtually surface and virtually polycyclic groups, and give an example of a group with solvable conjugacy problem but unsolvable twisted conjugacy problem. As an application, an alternative solution to the conjugacy problem in Aut(F2)Aut(F_2) is given

    A recursive presentation for Mihailova's subgroup

    Get PDF
    "Vegeu el resum a l'inici del document del fitxer adjunt"

    A recursive presentation for Mihailova's subgroup

    Get PDF
    We give an explicit recursive presentation for Mihailova's sub- group M(H) of Fn Fn corresponding to a nite, concise and Pei er aspherical presentation H = hx1; : : : ; xn jR1; : : : ;Rmi. This partially answers a question of R.I. Grigorchuk, [8, Problem 4.14]. As a corollary, we construct a nitely generated recursively presented orbit undecidable subgroup of Aut(F3)Postprint (published version

    The subgroup identification problem for finitely presented groups

    Full text link
    We introduce the subgroup identification problem, and show that there is a finitely presented group G for which it is unsolvable, and that it is uniformly solvable in the class of finitely presented locally Hopfian groups. This is done as an investigation into the difference between strong and weak effective coherence for finitely presented groups.Comment: 11 pages. This is the version submitted for publicatio
    corecore