3,4-Dihydr­oxy-N′-(2-hydroxy­benzyl­idene)benzohydrazide–methanol–water (2/1/3)

The asymmetric unit of the title compound, C14H12N2O4·0.5CH4O·1.5H2O, consists of two Schiff base mol­ecules, three water mol­ecules and one methanol mol­ecule. The dihedral angle between the two benzene rings is 7.8 (2)° in one of the mol­ecules and 4.0 (2)° in the other. Intra­molecular O—H⋯O and O—H⋯N hydrogen bonds are observed. Mol­ecules are linked into a three-dimensional network by O—H⋯O and N—H⋯O inter­molecular hydrogen bonds

N′-(4-Methoxy­benzyl­idene)-4-nitro­benzo­hydrazide methanol solvate

The title compound, C15H13N3O4·CH4O, was synthesized from the reaction of 4-methoxy­benzaldehyde with 4-nitro­benzohydrazide in methanol. The benzene rings of the Schiff base mol­ecule are nearly coplanar, making a dihedral angle of 7.0 (3)°. The methanol solvent mol­ecules are linked to the Schiff base mol­ecules by N—H⋯O, O—H⋯N and O—H⋯O hydrogen bonds, forming chains running parallel to the b axis

3,5-Dihydr­oxy-N′-[(2-hydr­oxy-1-naph­thyl)methyl­ene]benzohydrazide

In the title compound, C18H14N2O4, the dihedral angle between the benzene ring and the naphthyl ring system is 10.1 (2)°. The mol­ecule is nearly planar, with a mean deviation from the plane of 0.141 (2) Å for 24 non-H atoms. An intra­molecular O—H⋯N hydrogen bond forms a pseudo-6-membered ring and the mol­ecules are linked into sheets by inter­molecular N—H⋯O and O—H⋯O hydrogen bonds

N′-(2-Hydr­oxy-5-chloro­benzyl­idene)-4-nitro­benzohydrazide methanol solvate

The title compound, C14H10ClN3O4·CH4O, was synthesized from the reaction of 5-chloro­salicylaldehyde with 4-nitro­benzohydrazide in methanol. The Schiff base mol­ecule is nearly planar, with a dihedral angle of 9.1 (3)° between the two benzene rings. The methanol solvent mol­ecules are linked to the Schiff base mol­ecules by N—H⋯O, O—H⋯N and O—H⋯O hydrogen bonds, forming chains running parallel to the a axis

2,4-Dihydr­oxy-N′-(4-methoxy­benzyl­idene)benzohydrazide

The mol­ecule of the title compound, C15H14N2O4, displays a trans configuration with respect to the hydrazide C=N bond. The dihedral angle between the two benzene rings is 15.0 (2)°. In the crystal structure, mol­ecules are linked through inter­molecular O—H⋯N and O—H⋯O hydrogen bonds, forming layers parallel to the ab plane; an intramolecular N—H⋯O hydrogen bond is also present

(E)-4-Bromo-N′-(2-hydr­oxy-1-naphthyl­methyl­ene)benzohydrazide

The title compound, C18H13BrN2O2, was synthesized by the reaction of 2-hydr­oxy-1-naphthaldehyde with 4-bromo­benzohydrazide. This Schiff base mol­ecule has an E configuration about the C=N bond and is almost planar, the dihedral angle between the mean planes through the substituted benzene ring and the naphthyl system being 6.6 (2)°. There is an intra­molecular O—H⋯N hydrogen bond involving the naphthyl hydr­oxy substituent and the N′ atom of the hydrazide group. In the crystal structure, mol­ecules are linked through inter­molecular N—-H⋯O hydrogen bonds to form chains extending along the b direction

(E)-N′-(2,5-Dimethoxy­benzyl­idene)-2-(8-quinol­yloxy)acetohydrazide methanol solvate

The two mol­ecules in the asymmetric unit of the title compound, C20H19N3O4·CH4O, are paired via O—H⋯(O,N), N—H⋯O, and C—H⋯O hydrogen bonds. The mol­ecular skeleton of the acetohydrazide mol­ecule is close to planar; the benzene and quinoline mean planes form a dihedral angle of 3.9 (3)°. The crystal packing exhibits weak inter­molecular C—H⋯O hydrogen bonds and π–π inter­actions, indicated by short distances of 3.668 (3) Å, between the centroids of N-containing six-membered rings from neighbouring acetohydrazide mol­ecules

SIMULTANEOUS DETERMINATION OF CONTENTS OF THREE ACTIVE COMPONENTS IN JIEJIA TINCTURE BY HPLC METHOD

The objective of the study was to determine the contents of three active components in Jiejia tincture by establishing HPLC method. Test articles were prepared by ultrasonic extraction. Separation was performed using a Kromasil C18 (250 mm × 4.6 mm, 5 μm) chromatographic column, and gradient elution was performed with acetonitrile-0.3% phosphoric acid solution as the mobile phase at a volumetric flow rate of 0.80 mL/min. The contents of catechin, baicalin and berberine in Jiejia tincture were determined at the wavelength of 276 nm and a column temperature of 30 ℃. The results revealed that catechin showed a good linear relationship at the range of 100~800 μg/mL (r=0.9997); baicalin showed a good linear relationship at the range of 15~120 μg/mL (r=0.9996), and berberine at the range of 7~56 μg/mL (r=0.9995). Their average recovery rates were 99.67% (RSD 1.01%, n=6), 98.7% (RSD 1.93%, n=6) and 100.5% (RSD 2.88%, n=6) respectively. The study concluded that the high-performance liquid chromatography established in this study was simple, accurate and reproducible, and can also be used in the determination of catechin, baicalin and berberine contents in Jiejia tincture

(E)-4-Bromo-N′-(2-chloro­benzyl­idene)benzohydrazide

In the title compound, C14H10BrClN2O, the dihedral angle between the two benzene rings is 11.4 (2)°. In the crystal structure, mol­ecules are connected via inter­molecular N—H⋯O hydrogen bonds into one-dimensional chains running parallel to the c axis

(E)-N′-(5-Chloro-2-hydroxy­benzyl­idene)-3,5-dihydroxy­benzohydrazide mono­hydrate

In the title compound, C14H11ClN2O4·H2O, the dihedral angle between the two benzene rings is 8.5 (2)° and an intra­molecular O—H⋯N hydrogen bond is observed in the Schiff base mol­ecule. In the crystal structure, the water mol­ecule accepts an N—H⋯O hydrogen bond and makes O—H⋯O hydrogen bonds to two further Schiff base mol­ecules. Further inter­molecular O—H⋯O hydrogen bonds lead to the formation of layers parallel to the bc plane