704 research outputs found
Star-factors of tournaments
Let S_m denote the m-vertex simple digraph formed by m-1 edges with a common
tail. Let f(m) denote the minimum n such that every n-vertex tournament has a
spanning subgraph consisting of n/m disjoint copies of S_m. We prove that m lg
m - m lg lg m <= f(m) <= 4m^2 - 6m for sufficiently large m.Comment: 5 pages, 1 figur
Trees in tournaments
AbstractA digraph is said to be n-unavoidable if every tournament of order n contains it as a subgraph. Let f(n) be the smallest integer such that every oriented tree is f(n)-unavoidable. Sumner (see (Reid and Wormald, Studia Sci. Math. Hungaria 18 (1983) 377)) noted that f(n)⩾2n−2 and conjectured that equality holds. Häggkvist and Thomason established the upper bounds f(n)⩽12n and f(n)⩽(4+o(1))n. Let g(k) be the smallest integer such that every oriented tree of order n with k leaves is (n+g(k))-unavoidable. Häggkvist and Thomason (Combinatorica 11 (1991) 123) proved that g(k)⩽2512k3. Havet and Thomassé conjectured that g(k)⩽k−1. We study here the special case where the tree is a merging of paths (the union of disjoint paths emerging from a common origin). We prove that a merging of order n of k paths is (n+32(k2−3k)+5)-unavoidable. In particular, a tree with three leaves is (n+5)-unavoidable, i.e. g(3)⩽5. By studying trees with few leaves, we then prove that f(n)⩽385n−6
Trees in tournaments
AbstractA digraph is said to be n-unavoidable if every tournament of order n contains it as a subgraph. Let f(n) be the smallest integer such that every oriented tree is f(n)-unavoidable. Sumner (see (Reid and Wormald, Studia Sci. Math. Hungaria 18 (1983) 377)) noted that f(n)⩾2n−2 and conjectured that equality holds. Häggkvist and Thomason established the upper bounds f(n)⩽12n and f(n)⩽(4+o(1))n. Let g(k) be the smallest integer such that every oriented tree of order n with k leaves is (n+g(k))-unavoidable. Häggkvist and Thomason (Combinatorica 11 (1991) 123) proved that g(k)⩽2512k3. Havet and Thomassé conjectured that g(k)⩽k−1. We study here the special case where the tree is a merging of paths (the union of disjoint paths emerging from a common origin). We prove that a merging of order n of k paths is (n+32(k2−3k)+5)-unavoidable. In particular, a tree with three leaves is (n+5)-unavoidable, i.e. g(3)⩽5. By studying trees with few leaves, we then prove that f(n)⩽385n−6
k-Ary spanning trees contained in tournaments
A rooted tree is called a -ary tree, if all non-leaf vertices have exactly
children, except possibly one non-leaf vertex has at most children.
Denote by the minimum integer such that every tournament of order at
least contains a -ary spanning tree. It is well-known that every
tournament contains a Hamiltonian path, which implies that . Lu et al.
[J. Graph Theory {\bf 30}(1999) 167--176] proved the existence of , and
showed that and . The exact values of remain unknown
for . A result of Erd\H{o}s on the domination number of tournaments
implies . In this paper, we prove that and
.Comment: 11 pages, to appear in Discrete Applied Mathematic
Oriented trees and paths in digraphs
Which conditions ensure that a digraph contains all oriented paths of some
given length, or even a all oriented trees of some given size, as a subgraph?
One possible condition could be that the host digraph is a tournament of a
certain order. In arbitrary digraphs and oriented graphs, conditions on the
chromatic number, on the edge density, on the minimum outdegree and on the
minimum semidegree have been proposed. In this survey, we review the known
results, and highlight some open questions in the area
Largest Digraphs Contained IN All N-tournaments
Let f(n) (resp. g(n)) be the largest m such that there is a digraph (resp. a spanning weakly connected digraph) on n-vertices and m edges which is a subgraph of every tournament on n-vertices. We prove that n log2 n--cxn>=f(n) ~_g(n) ~- n log ~ n--c..n loglog n
On Seymour's and Sullivan's Second Neighbourhood Conjectures
For a vertex of a digraph, (, resp.) is the number of
vertices at distance 1 from (to, resp.) and is the number of
vertices at distance 2 from . In 1995, Seymour conjectured that for any
oriented graph there exists a vertex such that .
In 2006, Sullivan conjectured that there exists a vertex in such that
. We give a sufficient condition in terms of the number
of transitive triangles for an oriented graph to satisfy Sullivan's conjecture.
In particular, this implies that Sullivan's conjecture holds for all
orientations of planar graphs and of triangle-free graphs. An oriented graph
is an oriented split graph if the vertices of can be partitioned into
vertex sets and such that is an independent set and induces a
tournament. We also show that the two conjectures hold for some families of
oriented split graphs, in particular, when induces a regular or an almost
regular tournament.Comment: 14 pages, 1 figure
- …