31 research outputs found

    Boolean algebras and Lubell functions

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    Let 2[n]2^{[n]} denote the power set of [n]:={1,2,...,n}[n]:=\{1,2,..., n\}. A collection \B\subset 2^{[n]} forms a dd-dimensional {\em Boolean algebra} if there exist pairwise disjoint sets X0,X1,...,Xd⊆[n]X_0, X_1,..., X_d \subseteq [n], all non-empty with perhaps the exception of X0X_0, so that \B={X_0\cup \bigcup_{i\in I} X_i\colon I\subseteq [d]}. Let b(n,d)b(n,d) be the maximum cardinality of a family \F\subset 2^X that does not contain a dd-dimensional Boolean algebra. Gunderson, R\"odl, and Sidorenko proved that b(n,d)≤cdn−1/2d⋅2nb(n,d) \leq c_d n^{-1/2^d} \cdot 2^n where cd=10d2−21−ddd−2−dc_d= 10^d 2^{-2^{1-d}}d^{d-2^{-d}}. In this paper, we use the Lubell function as a new measurement for large families instead of cardinality. The Lubell value of a family of sets \F with \F\subseteq \tsupn is defined by h_n(\F):=\sum_{F\in \F}1/{{n\choose |F|}}. We prove the following Tur\'an type theorem. If \F\subseteq 2^{[n]} contains no dd-dimensional Boolean algebra, then h_n(\F)\leq 2(n+1)^{1-2^{1-d}} for sufficiently large nn. This results implies b(n,d)≤Cn−1/2d⋅2nb(n,d) \leq C n^{-1/2^d} \cdot 2^n, where CC is an absolute constant independent of nn and dd. As a consequence, we improve several Ramsey-type bounds on Boolean algebras. We also prove a canonical Ramsey theorem for Boolean algebras.Comment: 10 page

    An upper bound on the size of diamond-free families of sets

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    Let La(n,P)La(n,P) be the maximum size of a family of subsets of [n]={1,2,...,n}[n]=\{1,2,...,n\} not containing PP as a (weak) subposet. The diamond poset, denoted B2B_{2}, is defined on four elements x,y,z,wx,y,z,w with the relations x<y,zx<y,z and y,z<wy,z<w. La(n,P)La(n,P) has been studied for many posets; one of the major open problems is determining La(n,B2)La(n,B_{2}). Studying the average number of sets from a family of subsets of [n][n] on a maximal chain in the Boolean lattice 2[n]2^{[n]} has been a fruitful method. We use a partitioning of the maximal chains and introduce an induction method to show that La(n,B2)≤(2.20711+o(1))(n⌊n2⌋)La(n,B_{2})\leq(2.20711+o(1))\binom{n}{\left\lfloor \frac{n}{2}\right\rfloor }, improving on the earlier bound of (2.25+o(1))(n⌊n2⌋)(2.25+o(1))\binom{n}{\left\lfloor \frac{n}{2}\right\rfloor } by Kramer, Martin and Young.Comment: Accepted by JCTA. Writing is improved based on the suggestions of referee

    Ramsey numbers for partially-ordered sets

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    We present a refinement of Ramsey numbers by considering graphs with a partial ordering on their vertices. This is a natural extension of the ordered Ramsey numbers. We formalize situations in which we can use arbitrary families of partially-ordered sets to form host graphs for Ramsey problems. We explore connections to well studied Tur\'an-type problems in partially-ordered sets, particularly those in the Boolean lattice. We find a strong difference between Ramsey numbers on the Boolean lattice and ordered Ramsey numbers when the partial ordering on the graphs have large antichains.Comment: 18 pages, 3 figures, 1 tabl

    Rainbow Ramsey problems for the Boolean lattice

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    We address the following rainbow Ramsey problem: For posets P,QP,Q what is the smallest number nn such that any coloring of the elements of the Boolean lattice BnB_n either admits a monochromatic copy of PP or a rainbow copy of QQ. We consider both weak and strong (non-induced and induced) versions of this problem. We also investigate related problems on (partial) kk-colorings of BnB_n that do not admit rainbow antichains of size kk

    On diamond-free subposets of the Boolean lattice

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    The Boolean lattice of dimension two, also known as the diamond, consists of four distinct elements with the following property: A⊂B,C⊂DA\subset B,C\subset D. A diamond-free family in the nn-dimensional Boolean lattice is a subposet such that no four elements form a diamond. Note that elements BB and CC may or may not be related. There is a diamond-free family in the nn-dimensional Boolean lattice of size (2−o(1))(n⌊n/2⌋)(2-o(1)){n\choose\lfloor n/2\rfloor}. In this paper, we prove that any diamond-free family in the nn-dimensional Boolean lattice has size at most (2.25+o(1))(n⌊n/2⌋)(2.25+o(1)){n\choose\lfloor n/2\rfloor}. Furthermore, we show that the so-called Lubell function of a diamond-free family in the nn-dimensional Boolean lattice is at most 2.25+o(1)2.25+o(1), which is asymptotically best possible.Comment: 23 pages, 10 figures Accepted to Journal of Combinatorial Theory, Series

    On diamond-free subposets of the Boolean lattice

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    The Boolean lattice of dimension two, also known as the diamond, consists of four distinct elements with the following property: A ⊂ B, C ⊂ D. A diamondfree family in the n-dimensional Boolean lattice is a subposet such that no four elements form a diamond. Note that elements B and C may or may not be related. There is a diamond-free family in the n-dimensional Boolean lattice of size (2 − o(1)) n n/2 . In this paper, we prove that any diamond-free family in the ndimensional Boolean lattice has size at most (2.25 + o(1)) n n/2 . Furthermore, we show that the so-called Lubell function of a diamond-free family in the ndimensional Boolean lattice which contains the empty set is at most 2.25 + o(1), which is asympotically best possible
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