3 research outputs found

    Evaluation of a Special Hankel Determinant of Binomial Coefficients

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    This paper makes use of the recently introduced technique of γ\gamma-operators to evaluate the Hankel determinant with binomial coefficient entries ak=(3k)!/(2k)!k!a_k = (3 k)! / (2k)! k!. We actually evaluate the determinant of a class of polynomials ak(x)a_k(x) having this binomial coefficient as constant term. The evaluation in the polynomial case is as an almost product, i.e. as a sum of a small number of products. The γ\gamma-operator technique to find the explicit form of the almost product relies on differential-convolution equations and establishes a second order differential equation for the determinant. In addition to x=0x=0, product form evaluations for x=35,34,32,3x = \frac{3}{5}, \frac{3}{4}, \frac{3}{2}, 3 are also presented. At x=1x=1, we obtain another almost product evaluation for the Hankel determinant with ak=(3k+1)!/(2k+1)!k!a_k = ( 3 k+1) ! / (2k+1)!k!

    Evaluation of a Special Hankel Determinant of Binomial Coefficients

    Get PDF
    International audienceThis paper makes use of the recently introduced technique of γ\gamma-operators to evaluate the Hankel determinant with binomial coefficient entries ak=(3k)!/(2k)!k!a_k = (3 k)! / (2k)! k!. We actually evaluate the determinant of a class of polynomials ak(x)a_k(x) having this binomial coefficient as constant term. The evaluation in the polynomial case is as an almost product, i.e. as a sum of a small number of products. The γ\gamma-operator technique to find the explicit form of the almost product relies on differential-convolution equations and establishes a second order differential equation for the determinant. In addition to x=0x=0, product form evaluations for x=35,34,32,3x = \frac{3}{5}, \frac{3}{4}, \frac{3}{2}, 3 are also presented. At x=1x=1, we obtain another almost product evaluation for the Hankel determinant with ak=(3k+1)!/(2k+1)!k!a_k = ( 3 k+1) ! / (2k+1)!k!
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