9 research outputs found
Twins in words and long common subsequences in permutations
A large family of words must contain two words that are similar. We
investigate several problems where the measure of similarity is the length of a
common subsequence.
We construct a family of n^{1/3} permutations on n letters, such that LCS of
any two of them is only cn^{1/3}, improving a construction of Beame, Blais, and
Huynh-Ngoc. We relate the problem of constructing many permutations with small
LCS to the twin word problem of Axenovich, Person and Puzynina. In particular,
we show that every word of length n over a k-letter alphabet contains two
disjoint equal subsequences of length cnk^{-2/3}.
Many problems are left open.Comment: 18+epsilon page
Universal arrays
A word on symbols is a sequence of letters from a fixed alphabet of size
. For an integer , we say that a word is -universal if, given
an arbitrary word of length , one can obtain it by removing entries from
. It is easily seen that the minimum length of a -universal word on
symbols is exactly . We prove that almost every word of size
is -universal with high probability, where is an explicit constant
whose value is roughly . Moreover, we show that the -universality
property for uniformly chosen words exhibits a sharp threshold. Finally, by
extending techniques of Alon [Geometric and Functional Analysis 27 (2017), no.
1, 1--32], we give asymptotically tight bounds for every higher dimensional
analogue of this problem.Comment: 12 page
On abelian saturated infinite words
Let f:Z+âR be an increasing function. We say that an infinite word w is abelian f(n)-saturated if each factor of length n contains Î(f(n)) abelian nonequivalent factors. We show that binary infinite words cannot be abelian n2-saturated, but, for any Δ>0, they can be abelian n2âΔ-saturated. There is also a sequence of finite words (wn), with |wn|=n, such that each wn contains at least Cn2 abelian nonequivalent factors for some constant C>0. We also consider saturated words and their connection to palindromic richness in the case of equality and k-abelian equivalence.</p