55 research outputs found
4-Chloro-7-hydroxy-6-methyl-1,7-naphthyridin-8(7H)-one
The title compound, C9H7ClN2O2, was prepared by reaction of methyl 4-chloro-3-(prop-1-ynyl)picolinate with hydroxylamine in MeOH/KOH solution. The two essentially planar molecules which make up the asymmetric unit have almost identical geometries and and are linked into dimeric aggregates via pairs of O—H⋯O hydrogen bonds. These aggregates have almost perfect inversion symmetry; however, quite unusually, the inversion center of the dimer does not coincide with the crystallographic inversion center
trans-4-(2-Amino-5-bromo-6-methylpyrimidin-4-ylamino)-1-methylcyclohexanol
The title compound, C12H19BrN4O, represents the minor component of the two products obtained in a series of transformations involving the Grignard reaction of tert-butoxycarbonyl-protected 4-aminocyclohexanone with MeMgBr, and subsequent interaction of the obtained amino-substituted cyclohexanol with 4-chloro-6-methylpyrimidin-2-amine followed by bromination with N-bromosuccinimide. The X-ray structure showed that this product represents a trans isomer with respect to the amino and hydroxy substituents in the cyclohexyl ring; the dihedral angle between the aminopyrimidine plane and the (noncrystallographic) mirror plane of the substituted cyclohexyl fragment is 33.6 (3)°. Only two of the four potentially ‘active’ H atoms participate in intermolecular N—H⋯O and O—H⋯N hydrogen bonds, linking the molecules into layers parallel to the (10) plane
Methyl 3-[3-(ethoxycarbonyl)thioureido]-1H-pyrazole-5-carboxylate
The title compound, C9H12N4O4S, was proven to be the product of the reaction of methyl 5-amino-1H-pyrazole-3-carboxylate with ethyl isothiocyanatocarbonate. All non-H atoms of the molecule are planar, the mean deviation from the least squares plane being 0.048 Å. The intramolecular N—H⋯O bond involving the NH-group, which links the thiourea and pyrazole fragments, closes a six-membered pseudo-heterocyclic ring, and two more hydrogen bonds (N—H⋯O with the participation of the pyrazole NH group and N—H⋯S involving the second thiourea NH group) link the molecules into infinite chains running along [10]
2-Chloro-4-(1H-pyrazol-1-yl)-5-(trifluoromethyl)pyrimidine
The reaction of 2,4-dichloro-5-(trifluoromethyl)pyrimidine with 1H-pyrazole gave two structural isomers in a 1:1 ratio that were separable by chromatography. The title compound, C8H4ClF3N4, was the first product to elute and was characterized in the present study to confirm that substitution by the pyrazolyl group had occurred at position 4. The molecule (with the exception of the F atoms) is essentially planar, with a mean deviation of 0.034 Å from the least-squares plane through all non-H and non-F atoms. The bond angles in the pyrimidine ring show a pronounced alternating pattern with three angles, including those at the two N atoms being narrower, and the remaining three wider than 120°
2-Morpholino-4-oxo-4,5-dihydrothiophene-3-carbonitrile
The title compound, C9H10N2O2S, was obtained from the treatment of ethyl 4-cyano-3-hydroxy-5-morpholinothiophene-2-carboxylate with concentrated HCl. The mean plane of the essentially planar dihydrothiophene ring is almost orthogonal to the mirror plane of the N-morpholine substituent, making a dihedral angle of 87.2 (2)°
5-Bromo-1H-thieno[2,3-d]imidazole
The crystal structure of the title compound, C5H3BrN2S, shows that bromination of 1H-thieno[2,3-d]imidazole with N-bromosuccinimide in acetonitrile occurs at position 5 of the bicyclic system. The molecule is almost planar, with a mean deviation of 0.015 Å from the least-squares plane through all the non-H atoms. In the crystal, N—H⋯N hydrogen bonds link the molecules into infinite C(4) chains running along [101]
3-Amino-5-bromo-2-iodopyridine
The reaction of 3-amino-5-bromopyridine with N-iodosuccinimide in the presence of acetic acid produces the title compound, C5H4BrIN, with an iodo substituent in position 2 of the pyridine ring. The crystal structure features rather weak intermolecular N—H⋯N hydrogen bonds linking the molecules into chains along the z axis of the crystal
tert-Butyl 4-(1-methyl-1H-pyrazol-5-yl)piperidine-1-carboxylate
The reaction of (E)-tert-butyl 4-[3-(dimethylamino)acryloyl]piperidine-1-carboxylate with methylhydrazine leads to the formation of the title compound, C14H23N3O2, with a 1-methyl-1H-pyrazol-5-yl substituent. The plane of the pyrazole ring forms a dihedral angle of 33.4 (1)° with the approximate mirror plane of the piperidine ring
2-(6-Bromo-3-pyridyl)-8-methylimidazo[1,2-a]pyrazine
The structure of the title compound, C12H9BrN4, prepared by the reaction of 2-bromo-1-(6-bromo-3-pyridyl)ethanone with 2-amino-3-methylpyrazine indicates that the compound with the bromopyridyl substituent at position 2 of the imidazopyrazine fused-ring system represents the major product of this reaction. The plane of the pyridine ring forms a dihedral angle of 16.2 (2)° with the essentially planar (r.m.s. deviation = 0.006 Å) imidazopyrazine system. In the crystal, molecules are linked by weak C—H⋯N interactions
6-(2,6-Dimethylphenyl)pyrido[2,3-d]pyrimidin-7-amine
In the title compound, C15H14N4, the pyrido[2,3-d]pyrimidine system is almost ideally planar (r.m.s. deviation 0.028 Å) with its mean plane almost orthogonal to the 2,6-dimethylphenyl plane. The dihedral angle formed by these planes [87.3 (2)°] is close to the predicted value (89.7°) obtained by molecular-mechanics force-field calculations. Only one of the two active amine H atoms participates in hydrogen bonding, which links molecules into centrosymmetric dimers
- …