820 research outputs found

    Congruences concerning Jacobi polynomials and Ap\'ery-like formulae

    Full text link
    Let p>5p>5 be a prime. We prove congruences modulo p3dp^{3-d} for sums of the general form k=0(p3)/2(2kk)tk/(2k+1)d+1\sum_{k=0}^{(p-3)/2}\binom{2k}{k}t^k/(2k+1)^{d+1} and k=1(p1)/2(2kk)tk/kd\sum_{k=1}^{(p-1)/2}\binom{2k}{k}t^k/k^d with d=0,1d=0,1. We also consider the special case t=(1)d/16t=(-1)^{d}/16 of the former sum, where the congruences hold modulo p5dp^{5-d}.Comment: to appear in Int. J. Number Theor

    Some congruences involving central q-binomial coefficients

    Full text link
    Motivated by recent works of Sun and Tauraso, we prove some variations on the Green-Krammer identity involving central q-binomial coefficients, such as k=0n1(1)kq(k+12)[2kk]q(n5)qn4/5(modΦn(q)), \sum_{k=0}^{n-1}(-1)^kq^{-{k+1\choose 2}}{2k\brack k}_q \equiv (\frac{n}{5}) q^{-\lfloor n^4/5\rfloor} \pmod{\Phi_n(q)}, where (np)\big(\frac{n}{p}\big) is the Legendre symbol and Φn(q)\Phi_n(q) is the nnth cyclotomic polynomial. As consequences, we deduce that \sum_{k=0}^{3^a m-1} q^{k}{2k\brack k}_q &\equiv 0 \pmod{(1-q^{3^a})/(1-q)}, \sum_{k=0}^{5^a m-1}(-1)^kq^{-{k+1\choose 2}}{2k\brack k}_q &\equiv 0 \pmod{(1-q^{5^a})/(1-q)}, for a,m1a,m\geq 1, the first one being a partial q-analogue of the Strauss-Shallit-Zagier congruence modulo powers of 3. Several related conjectures are proposed.Comment: 16 pages, detailed proofs of Theorems 4.1 and 4.3 are added, to appear in Adv. Appl. Mat

    On the interplay between hypergeometric series, Fourier-Legendre expansions and Euler sums

    Full text link
    In this work we continue the investigation about the interplay between hypergeometric functions and Fourier-Legendre (FL\textrm{FL}) series expansions. In the section "Hypergeometric series related to π,π2\pi,\pi^2 and the lemniscate constant", through the FL-expansion of [x(1x)]μ\left[x(1-x)\right]^\mu (with μ+114N\mu+1\in\frac{1}{4}\mathbb{N}) we prove that all the hypergeometric series n0(1)n(4n+1)p(n)[14n(2nn)]3,n0(4n+1)p(n)[14n(2nn)]4, \sum_{n\geq 0}\frac{(-1)^n(4n+1)}{p(n)}\left[\frac{1}{4^n}\binom{2n}{n}\right]^3,\quad \sum_{n\geq 0}\frac{(4n+1)}{p(n)}\left[\frac{1}{4^n}\binom{2n}{n}\right]^4, n0(4n+1)p(n)2[14n(2nn)]4,  n01p(n)[14n(2nn)]3,  n01p(n)[14n(2nn)]2\quad \sum_{n\geq 0}\frac{(4n+1)}{p(n)^2}\left[\frac{1}{4^n}\binom{2n}{n}\right]^4,\; \sum_{n\geq 0}\frac{1}{p(n)}\left[\frac{1}{4^n}\binom{2n}{n}\right]^3,\; \sum_{n\geq 0}\frac{1}{p(n)}\left[\frac{1}{4^n}\binom{2n}{n}\right]^2 return rational multiples of 1π,1π2\frac{1}{\pi},\frac{1}{\pi^2} or the lemniscate constant, as soon as p(x)p(x) is a polynomial fulfilling suitable symmetry constraints. Additionally, by computing the FL-expansions of logxx\frac{\log x}{\sqrt{x}} and related functions, we show that in many cases the hypergeometric p+1Fp(,z)\phantom{}_{p+1} F_{p}(\ldots , z) function evaluated at z=±1z=\pm 1 can be converted into a combination of Euler sums. In particular we perform an explicit evaluation of n01(2n+1)2[14n(2nn)]2,n01(2n+1)3[14n(2nn)]2. \sum_{n\geq 0}\frac{1}{(2n+1)^2}\left[\frac{1}{4^n}\binom{2n}{n}\right]^2,\quad \sum_{n\geq 0}\frac{1}{(2n+1)^3}\left[\frac{1}{4^n}\binom{2n}{n}\right]^2. In the section "Twisted hypergeometric series" we show that the conversion of some p+1Fp(,±1)\phantom{}_{p+1} F_{p}(\ldots,\pm 1) values into combinations of Euler sums, driven by FL-expansions, applies equally well to some twisted hypergeometric series, i.e. series of the form n0anbn\sum_{n\geq 0} a_n b_n where ana_n is a Stirling number of the first kind and n0bnzn=p+1Fp(;z)\sum_{n\geq 0}b_n z^n = \phantom{}_{p+1} F_{p}(\ldots;z)
    corecore