6 research outputs found
Sidorenko's conjecture for higher tree decompositions
This is a companion note to our paper 'Some advances on Sidorenko's
conjecture', elaborating on a remark in that paper that the approach which
proves Sidorenko's conjecture for strongly tree-decomposable graphs may be
extended to a broader class, comparable to that given in work of Szegedy,
through further iteration.Comment: 7 pages, unpublished not
Some advances on Sidorenko's conjecture
A bipartite graph H is said to have Sidorenko’s property if the probability that the uniform random mapping from V(H) to the vertex set of any graph G is a homomorphism is at least the product over all edges in H of the probability that the edge is mapped to an edge of G. In this paper, we provide three distinct families of bipartite graphs that have Sidorenko’s property. First, using branching random walks, we develop an embedding algorithm which allows us to prove that bipartite graphs admitting a certain type of tree decomposition have Sidorenko’s property. Second, we use the concept of locally dense graphs to prove that subdivisions of certain graphs, including cliques, have Sidorenko’s property. Third, we prove that if H has Sidorenko’s property, then the Cartesian product of H with an even cycle also has Sidorenko’s property
Some advances on Sidorenko's conjecture
A bipartite graph H is said to have Sidorenko's property if the probability that the uniform random mapping from V(H) to the vertex set of any graph G is a homomorphism is at least the product over all edges in H of the probability that the edge is mapped to an edge of G. In this paper, we provide three distinct families of bipartite graphs that have Sidorenko's property. First, using branching random walks, we develop an embedding algorithm which allows us to prove that bipartite graphs admitting a certain type of tree decomposition have Sidorenko's property. Second, we use the concept of locally dense graphs to prove that subdivisions of certain graphs, including cliques, have Sidorenko's property. Third, we prove that if H has Sidorenko's property, then the Cartesian product of H with an even cycle also has Sidorenko's property