8 research outputs found

    Saturation Numbers for Berge Cliques

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    Let FF be a graph and H\mathcal{H} be a hypergraph, both embedded on the same vertex set. We say H\mathcal{H} is a Berge-FF if there exists a bijection ϕ:E(F)→E(H)\phi:E(F)\to E(\mathcal{H}) such that e⊆ϕ(e)e\subseteq \phi(e) for all e∈E(F)e\in E(F). We say H\mathcal{H} is Berge-FF-saturated if H\mathcal{H} does not contain any Berge-FF, but adding any missing edge to H\mathcal{H} creates a copy of a Berge-FF. The saturation number satk(n,Berge-F)\mathrm{sat}_k(n,\text{Berge-}F) is the least number of edges in a Berge-FF-saturated kk-uniform hypergraph on nn vertices. We show satk(n,Berge-Kℓ)∼ℓ−2k−1n, \mathrm{sat}_k(n,\text{Berge-}K_\ell)\sim \frac{\ell-2}{k-1}n, for all k,ℓ≥3k,\ell\geq 3. Furthermore, we provide some sufficient conditions to imply that satk(n,Berge-F)=O(n)\mathrm{sat}_k(n,\text{Berge-}F)=O(n) for general graphs FF.Comment: 16 pages, 1 figur

    Linearity of Saturation for Berge Hypergraphs

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    For a graph F, we say a hypergraph H is Berge-F if it can be obtained from F be replacing each edge of F with a hyperedge containing it. We say a hypergraph is Berge-F-saturated if it does not contain a Berge-F, but adding any hyperedge creates a copy of Berge-F. The k-uniform saturation number of Berge-F, satk(n, Berge-F) is the fewest number of edges in a Berge-F-saturated k-uniform hypergraph on n vertices. We show that satk(n, Berge-F) = O(n) for all graphs F and uniformities 3 ≤ k ≤ 5, partially answering a conjecture of English, Gordon, Graber, Methuku, and Sullivan. We also extend this conjecture to Berge copies of hypergraph
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