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Neutron electric dipole moment from lattice QCD

Abstract

We carry out a feasibility study for the lattice QCD calculation of the neutron electric dipole moment (NEDM) in the presence of the θ\theta term. We develop the strategy to obtain the nucleon EDM from the CP-odd electromagnetic form factor F3F_3 at small θ\theta, in which NEDM is given by limq20θF3(q2)/(2mN)\lim_{q^2\to 0}\theta F_3(q^2)/(2m_N) where qq is the momentum transfer and mNm_N is the nucleon mass. We first derive a formula which relates F3F_3, a matrix element of the electromagnetic current between nucleon states, with vacuum expectation values of nucleons and/or the current. In the expansion of θ\theta, the parity-odd part of the nucleon-current-nucleon three-point function contains contributions not only from the parity-odd form factors but also from the parity-even form factors multiplied by the parity-odd part of the nucleon two-point function, and therefore the latter contribution must be subtracted to extract F3F_3. We then perform an explicit lattice calculation employing the domain-wall quark action with the RG improved gauge action in quenched QCD at a12a^{-1}\simeq 2 GeV on a 163×32×1616^3\times 32\times 16 lattice. At the quark mass mfa=0.03m_f a =0.03, corresponding to mπ/mρ0.63m_\pi/m_\rho \simeq 0.63, we accumulate 730 configurations, which allow us to extract the parity-odd part in both two- and three-point functions. Employing two different Dirac γ\gamma matrix projections, we show that a consistent value for F3F_3 cannot be obtained without the subtraction described above. We obtain F3(q20.58GeV2)/(2mN)=F_3(q^2\simeq 0.58 \textrm{GeV}^2)/(2m_N) = -0.024(5) ee\cdotfm for the neutron and F3(q20.58GeV2)/(2mN)=F_3(q^2\simeq 0.58 \textrm{GeV}^2)/(2m_N) = 0.021(6) ee\cdotfm for the proton.Comment: LaTeX2e, 43 pages, 42 eps figures, uses revtex4 and graphicx, comments added and typos corrected, final version to appear in Phys. Rev.

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