For N=1,2,..., let S_N be a simple random sample of size n=n_N from a
population A_N of size N, where 0<=n<=N. Then with f_N=n/N, the sampling
fraction, and 1_A the inclusion indicator that A is in S_N, for any H a subset
of A_N of size k>= 0, the high order correlations Corr(k) = E (\prod_{A \in H}
(1_A-f_N)) depend only on k, and if the sampling fraction f_N -> f as N ->
infinity, then N^{k/2}Corr(k) -> [f(f-1)]^{k/2}EZ^k, k even and
N^{(k+1)/2}Corr(k) -> [f(f-1)]^{(k-1)/2}(2f-1)(1/3)(k-1)EZ^{k+1}, k odd where Z
is a standard normal random variable. This proves a conjecture given in [2].Comment: 32 page
