The Competitive O–H versus C–H Bond Activation of Ethanol and Methanol by VO<sub>2</sub><sup>+</sup> in Gas Phase: A DFT Study

Abstract

The activation of ethanol and methanol by VO<sub>2</sub><sup>+</sup> in gas phase has been theoretically investigated by using density functional theory (DFT). For the VO<sub>2</sub><sup>+</sup>/ethanol system, the activation energy (Δ<i>E</i>) is found to follow the order of Δ<i>E</i>(C<sup>β</sup>–H) < Δ<i>E</i>(C<sup>α</sup>–H) ≈ Δ<i>E</i>(O–H). Loss of methyl and glycol occurs respectively via O–H and C<sup>β</sup>–H activation, while acetaldehyde elimination proceeds through two comparable O–H and C<sup>α</sup>–H activations yielding both VO­(H<sub>2</sub>O)<sup>+</sup> and V­(OH)<sub>2</sub><sup>+</sup>. Loss of water not only gives rise to VO­(CH<sub>3</sub>CHO)<sup>+</sup> via both O–H and C<sup>α</sup>–H activation but also forms VO<sub>2</sub>(C<sub>2</sub>H<sub>4</sub>)<sup>+</sup> via C<sup>β</sup>–H activation. The major product of ethylene is formed via both O–H and C<sup>β</sup>–H activation for yielding VO­(OH)<sub>2</sub><sup>+</sup> and VO<sub>2</sub>(H<sub>2</sub>O)<sup>+</sup>. In the methanol reaction, both initial O–H and C<sup>α</sup>–H activation accounts for formaldehyde and water elimination, but the former pathway is preferred

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