The Competitive O–H versus C–H Bond
Activation of Ethanol and Methanol by VO<sub>2</sub><sup>+</sup> in
Gas Phase: A DFT Study
- Publication date
- Publisher
Abstract
The
activation of ethanol and methanol by VO<sub>2</sub><sup>+</sup> in
gas phase has been theoretically investigated by using density functional
theory (DFT). For the VO<sub>2</sub><sup>+</sup>/ethanol system, the
activation energy (Δ<i>E</i>) is found to follow the
order of Δ<i>E</i>(C<sup>β</sup>–H) <
Δ<i>E</i>(C<sup>α</sup>–H) ≈ Δ<i>E</i>(O–H). Loss of methyl and glycol occurs respectively
via O–H and C<sup>β</sup>–H activation, while
acetaldehyde elimination proceeds through two comparable O–H
and C<sup>α</sup>–H activations yielding both VO(H<sub>2</sub>O)<sup>+</sup> and V(OH)<sub>2</sub><sup>+</sup>. Loss of
water not only gives rise to VO(CH<sub>3</sub>CHO)<sup>+</sup> via
both O–H and C<sup>α</sup>–H activation but also
forms VO<sub>2</sub>(C<sub>2</sub>H<sub>4</sub>)<sup>+</sup> via C<sup>β</sup>–H activation. The major product of ethylene
is formed via both O–H and C<sup>β</sup>–H activation
for yielding VO(OH)<sub>2</sub><sup>+</sup> and VO<sub>2</sub>(H<sub>2</sub>O)<sup>+</sup>. In the methanol reaction, both initial O–H
and C<sup>α</sup>–H activation accounts for formaldehyde
and water elimination, but the former pathway is preferred