"A well known and unexpected result of Guibas and Odlyzko states that the set of all periods of a word is independent of the alphabet size (alphabets with one symbol are excluded here). More specifically, for every word u, there exists a word v over the alphabet {0, 1} such that u and v have the same length and the same set of periods. Recently, Blanchet-Sadri and Chriscoe extended this fundamental result to words with one "do not know" symbol also called partial words with one hole. They showed that for every partial word u with one hole, there exists a partial word v with at most one hole over the alphabet {0, 1} such that u and v have the same length, the same set of periods, the same set of weak periods, and H(v) H(u)," where H(u) (respectively, H(v)) denotes the set of holes of u (respectively, v). In this paper, we extend this result further to a large class of partial words. Given a partial word u belonging to that class, our proof provides an algorithm to compute a partial word v over {0, 1} sharing the same length and same sets of periods and weak periods as u, and satisfying H(v) H(u)."--Abstract from author supplied metadata
