Since solving Dave Silverman\u27s problem of dividing a 6-letter word into two 3-letter words in all possible ways -- a total of ten word pairs -- I have toyed with the idea of doing the same thing to an 8-letter word, dividing it into pairs of 4-letter words. The number of possible combinations here is 35, and Silverman implied that finding more than half a dozen pairs was impossible if one sticks to the Second and Third Editions of Webster\u27s Unabridged
