In the title compound, C19H22N3O+·Br−, the imidazole ring is approximately coplanar with the pyridine ring [dihedral angle = 0.88 (13)°] and nearly perpendicular to the benzene ring [dihedral angle = 81.70 (13)°]. O—H⋯Br and C—H⋯Br hydrogen bonding helps to stabilize the crystal structure