On the proportion of elements of prime order in finite symmetric groups

Abstract

We give a short proof for an explicit upper bound on the proportion of permutations of a given prime order pp, acting on a finite set of given size nn, which is sharp for certain nn and pp. Namely, we prove that if n≑k(modp)n\equiv k\pmod{p} with 0≀k≀pβˆ’10\leq k\leq p-1, then this proportion is at most (pβ‹…k!)βˆ’1(p\cdot k!)^{-1} with equality if and only if p≀n<2np\leq n<2n.Comment: 7 page

    Similar works

    Full text

    thumbnail-image

    Available Versions