The braid groups Bn,m(RP2)B_{n,m}(\mathbb{R}P^2) and the splitting problem of the generalised Fadell-Neuwirth short exact sequence

Abstract

32 pages, 11 figuresLet n,m∈Nn,m\in \mathbb{N}, and let Bn,m(RP2)B_{n,m}(\mathbb{R}P^2) be the set of (n+m)(n + m)-braids of the projective plane whose associated permutation lies in the subgroup Sn×SmS_n\times S_m of the symmetric group Sn+mS_{n+m}. We study the splitting problem of the following generalisation of the Fadell-Neuwirth short exact sequence: 1→Bm(RP2∖{x1,…,xn})→Bn,m(RP2)→qˉBn(RP2)→1,1\rightarrow B_m(\mathbb{R}P^2 \setminus \{x_1,\dots,x_n\})\rightarrow B_{n,m}(\mathbb{R}P^2)\xrightarrow{\bar{q}} B_n(\mathbb{R}P^2)\rightarrow 1, where the map qˉ\bar{q} can be considered geometrically as the epimorphism that forgets the last mm strands, as well as the existence of a section of the corresponding fibration q:Fn+m(RP2)/Sn×Sm→Fn(RP2)/Snq:F_{n+m}(\mathbb{R}P^2)/S_n\times S_m\to F_{n}(\mathbb{R}P^2)/S_n, where we denote by Fn(RP2)F_n(\mathbb{R}P^2) the nthn^{th} ordered configuration space of the projective plane RP2\mathbb{R}P^2. Our main results are the following: if n=1n=1 the homomorphism qˉ\bar{q} and the corresponding fibration qq admits no section, while if n=2n=2, then qˉ\bar{q} and qq admit a section. For n≥3n\geq 3, we show that if qˉ\bar{q} and qq admit a section then m≡0,(n−1)2 mod n(n−1)m\equiv 0, (n-1)^2\ \textrm{mod}\ n(n-1). Moreover, using geometric constructions, we show that the homomorphism qˉ\bar{q} and the fibration qq admit a section for m=kn(2n−1)(2n−2)m=kn(2n-1)(2n-2), where k≥1 k\geq1, and for m=2n(n−1)m=2n(n-1). In addition, we show that for m≥3m\geq3, Bm(RP2∖{x1,…,xn})B_m(\mathbb{R}P^2\setminus\{x_1,\dots,x_n\}) is not residually nilpotent and for m≥5m\geq 5, it is not residually solvable

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