47 research outputs found

    The circle method and bounds for LL-functions - I

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    Let ff be a Hecke-Maass or holomorphic primitive cusp form of arbitrary level and nebentypus, and let Ο‡\chi be a primitive character of conductor MM. For the twisted LL-function L(s,fβŠ—Ο‡)L(s,f\otimes \chi) we establish the hybrid subconvex bound L(1/2+it,fβŠ—Ο‡)β‰ͺ(M(3+∣t∣))1/2βˆ’1/18+Ξ΅, L(1/2+it,f\otimes\chi)\ll (M(3+|t|))^{1/2-1/18+\varepsilon}, for t∈Rt\in \mathbb R. The implied constant depends only on the form ff and Ξ΅\varepsilon.Comment: 8 page

    Bounds for twisted symmetric square LL-functions

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    Let f∈Sk(N,ψ)f\in S_k(N,\psi) be a newform, and let Ο‡\chi be a primitive character of conductor qβ„“q^{\ell}. Assume that qq is a prime and β„“>1\ell>1. In this paper we describe a method to establish convexity breaking bounds of the form L(\tfrac{1}{2},\Sym f\otimes\chi)\ll_{f,\varepsilon} q^{3/4\ell-\delta_{\ell}+\varepsilon} for some Ξ΄β„“>0\delta_{\ell}>0 and any Ξ΅>0\varepsilon>0. In particular, for β„“=3\ell=3 we show that the bound holds with Ξ΄β„“=1/4\delta_{\ell}=1/4.Comment: 19 pages, (Extensively revised version

    Shifted convolution sums for GL(3)Γ—GL(2)GL(3)\times GL(2)

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    For the shifted convolution sum Dh(X)=βˆ‘m=1∞λ1(1,m)Ξ»2(m+h)V(mX) D_h(X)=\sum_{m=1}^\infty\lambda_1(1,m)\lambda_2(m+h)V(\frac{m}{X}) where Ξ»1(1,m)\lambda_1(1,m) are the Fourier coefficients of a SL(3,Z)SL(3,\mathbb Z) Maass form Ο€1\pi_1, and Ξ»2(m)\lambda_2(m) are those of a SL(2,Z)SL(2,\mathbb Z) Maass or holomorphic form Ο€2\pi_2, and 1β‰€βˆ£h∣β‰ͺX1+Ξ΅1\leq |h| \ll X^{1+\varepsilon}, we establish the bound Dh(X)β‰ͺΟ€1,Ο€2,Ξ΅X1βˆ’(1/20)+Ξ΅. D_h(X)\ll_{\pi_1,\pi_2,\varepsilon} X^{1-(1/20)+\varepsilon}. The bound is uniform with respect to the shift hh

    Determination of GL(3)GL(3) Hecke-Maass forms from twisted central values

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    Suppose Ο€1\pi_1 and Ο€2\pi_2 are two Hecke-Maass cusp forms for SL(3,Z)SL(3,\mathbb{Z}) such that for all primitive character Ο‡\chi we have L(12,Ο€1βŠ—Ο‡)=L(12,Ο€2βŠ—Ο‡). L(\tfrac{1}{2},\pi_1\otimes\chi)=L(\tfrac{1}{2},\pi_2\otimes\chi). Then we show that Ο€1=Ο€2\pi_1=\pi_2.Comment: First draf
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