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Productively Lindel\"of spaces of countable tightness
Michael asked whether every productively Lindel\"of space is powerfully
Lindel\"of. Building of work of Alster and De la Vega, assuming the Continuum
Hypothesis, we show that every productively Lindel\"of space of countable
tightness is powerfully Lindel\"of. This strengthens a result of Tall and
Tsaban. The same methods also yield new proofs of results of Arkhangel'skii and
Buzyakova. Furthermore, assuming the Continuum Hypothesis, we show that a
productively Lindel\"of space is powerfully Lindel\"of if every open cover
of admits a point-continuum refinement consisting of basic open
sets. This strengthens a result of Burton and Tall. Finally, we show that
separation axioms are not relevant to Michael's question: if there exists a
counterexample (possibly not even ), then there exists a regular
(actually, zero-dimensional) counterexample.Comment: 7 page
-topology and compact cardinals
For a topological space , let be the space with
-topology of . For an uncountable cardinal , we prove that
the following are equivalent: (1) is -strongly compact. (2)
For every compact Hausdorff space , the Lindel\"of degree of is
. (3) For every compact Hausdorff space , the weak Lindel\"of
degree of is . This shows that the least
-strongly compact cardinal is the supremum of the Lindel\"of and the
weak Lindel\"of degrees of compact Hausdorff spaces with -topology.
We also prove the least measurable cardinal is the supremum of the extents of
compact Hausdorff spaces with -topology.
For the square of a Lindel\"of space, using weak -topology, we
prove that the following are consistent: (1) the least -strongly
compact cardinal is the supremum of the (weak) Lindel\"of degrees of the
squares of regular Lindel\"of spaces. (2) The least measurable cardinal
is the supremum of the extents of the squares of regular Lindel\"of
spaces
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