2,648 research outputs found

    Max flow vitality in general and stst-planar graphs

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    The \emph{vitality} of an arc/node of a graph with respect to the maximum flow between two fixed nodes ss and tt is defined as the reduction of the maximum flow caused by the removal of that arc/node. In this paper we address the issue of determining the vitality of arcs and/or nodes for the maximum flow problem. We show how to compute the vitality of all arcs in a general undirected graph by solving only 2(n1)2(n-1) max flow instances and, In stst-planar graphs (directed or undirected) we show how to compute the vitality of all arcs and all nodes in O(n)O(n) worst-case time. Moreover, after determining the vitality of arcs and/or nodes, and given a planar embedding of the graph, we can determine the vitality of a `contiguous' set of arcs/nodes in time proportional to the size of the set.Comment: 12 pages, 3 figure

    Single Source - All Sinks Max Flows in Planar Digraphs

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    Let G = (V,E) be a planar n-vertex digraph. Consider the problem of computing max st-flow values in G from a fixed source s to all sinks t in V\{s}. We show how to solve this problem in near-linear O(n log^3 n) time. Previously, no better solution was known than running a single-source single-sink max flow algorithm n-1 times, giving a total time bound of O(n^2 log n) with the algorithm of Borradaile and Klein. An important implication is that all-pairs max st-flow values in G can be computed in near-quadratic time. This is close to optimal as the output size is Theta(n^2). We give a quadratic lower bound on the number of distinct max flow values and an Omega(n^3) lower bound for the total size of all min cut-sets. This distinguishes the problem from the undirected case where the number of distinct max flow values is O(n). Previous to our result, no algorithm which could solve the all-pairs max flow values problem faster than the time of Theta(n^2) max-flow computations for every planar digraph was known. This result is accompanied with a data structure that reports min cut-sets. For fixed s and all t, after O(n^{3/2} log^{3/2} n) preprocessing time, it can report the set of arcs C crossing a min st-cut in time roughly proportional to the size of C.Comment: 25 pages, 4 figures; extended abstract appeared in FOCS 201

    Minimum Cycle Basis and All-Pairs Min Cut of a Planar Graph in Subquadratic Time

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    A minimum cycle basis of a weighted undirected graph GG is a basis of the cycle space of GG such that the total weight of the cycles in this basis is minimized. If GG is a planar graph with non-negative edge weights, such a basis can be found in O(n2)O(n^2) time and space, where nn is the size of GG. We show that this is optimal if an explicit representation of the basis is required. We then present an O(n3/2logn)O(n^{3/2}\log n) time and O(n3/2)O(n^{3/2}) space algorithm that computes a minimum cycle basis \emph{implicitly}. From this result, we obtain an output-sensitive algorithm that explicitly computes a minimum cycle basis in O(n3/2logn+C)O(n^{3/2}\log n + C) time and O(n3/2+C)O(n^{3/2} + C) space, where CC is the total size (number of edges and vertices) of the cycles in the basis. These bounds reduce to O(n3/2logn)O(n^{3/2}\log n) and O(n3/2)O(n^{3/2}), respectively, when GG is unweighted. We get similar results for the all-pairs min cut problem since it is dual equivalent to the minimum cycle basis problem for planar graphs. We also obtain O(n3/2logn)O(n^{3/2}\log n) time and O(n3/2)O(n^{3/2}) space algorithms for finding, respectively, the weight vector and a Gomory-Hu tree of GG. The previous best time and space bound for these two problems was quadratic. From our Gomory-Hu tree algorithm, we obtain the following result: with O(n3/2logn)O(n^{3/2}\log n) time and O(n3/2)O(n^{3/2}) space for preprocessing, the weight of a min cut between any two given vertices of GG can be reported in constant time. Previously, such an oracle required quadratic time and space for preprocessing. The oracle can also be extended to report the actual cut in time proportional to its size
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