The title compound, C15H15NO3, adopts the enol–imine tautomeric form. The two rings are twisted with respect to each other, making a dihedral angle of 44.08 (5)°. The 3-methoxy-2-[(E)-(4-methoxyphenyl)-iminomethyl]phenol unit is almost planar, the largest deviation from the mean plane being 0.047 (2) Å. Such a planar conformation might be related to the occurrence of an intramolecular O—H⋯N hydrogen bond. In the crystal, intermolecular C—H⋯O hydrogen bonds link the molecules into sheets parallel to (010). These sheets are interconnected by weak C—H⋯π interactions
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