Activating a flip-flop circuit by a current fast-rising slope impulse, the circuit occupies one of the two stable states, the stable state ‘one ‘ or ‘zero‘. In case of a perfect flip-flop symmetry over a large number of cycles, a noise causes the ratio of ‘ones ‘ and ‘ zeros ‘ is equal to one – 50 % position of a flip-flop. However, any imbalance in the system changes the probability of taking a ‘one ’ or a ‘zero’, and thus the ratio of ‘ones ’ and ‘zeros’. In this paper, the formula for equivalent voltage of the flip-flop circuit is derived. This voltage is incorporated into the flip-flop as a voltage source to restore 50 % position. The formula is derived for the first time. The results are useful for capacitance measurement and in capacitive sensor applications. PACS: 02.50.Ey; 84.30.Bv; 84.37.+q
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