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    Probabilistic lower bounds on maximal determinants of binary matrices

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    Let D(n){\mathcal D}(n) be the maximal determinant for nΓ—nn \times n {Β±1}\{\pm 1\}-matrices, and R(n)=D(n)/nn/2\mathcal R(n) = {\mathcal D}(n)/n^{n/2} be the ratio of D(n){\mathcal D}(n) to the Hadamard upper bound. Using the probabilistic method, we prove new lower bounds on D(n){\mathcal D}(n) and R(n)\mathcal R(n) in terms of d=nβˆ’hd = n-h, where hh is the order of a Hadamard matrix and hh is maximal subject to h≀nh \le n. For example, R(n)>(Ο€e/2)βˆ’d/2\mathcal R(n) > (\pi e/2)^{-d/2} if 1≀d≀31 \le d \le 3, and R(n)>(Ο€e/2)βˆ’d/2(1βˆ’d2(Ο€/(2h))1/2)\mathcal R(n) > (\pi e/2)^{-d/2}(1 - d^2(\pi/(2h))^{1/2}) if d>3d > 3. By a recent result of Livinskyi, d2/h1/2β†’0d^2/h^{1/2} \to 0 as nβ†’βˆžn \to \infty, so the second bound is close to (Ο€e/2)βˆ’d/2(\pi e/2)^{-d/2} for large nn. Previous lower bounds tended to zero as nβ†’βˆžn \to \infty with dd fixed, except in the cases d∈{0,1}d \in \{0,1\}. For dβ‰₯2d \ge 2, our bounds are better for all sufficiently large nn. If the Hadamard conjecture is true, then d≀3d \le 3, so the first bound above shows that R(n)\mathcal R(n) is bounded below by a positive constant (Ο€e/2)βˆ’3/2>0.1133(\pi e/2)^{-3/2} > 0.1133.Comment: 17 pages, 2 tables, 24 references. Shorter version of arXiv:1402.6817v4. Typos corrected in v2 and v3, new Lemma 7 in v4, updated references in v5, added Remark 2.8 and a reference in v6, updated references in v
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