28 research outputs found

    On an extremal problem for poset dimension

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    Let f(n)f(n) be the largest integer such that every poset on nn elements has a 22-dimensional subposet on f(n)f(n) elements. What is the asymptotics of f(n)f(n)? It is easy to see that f(n)n1/2f(n)\geqslant n^{1/2}. We improve the best known upper bound and show f(n)=O(n2/3)f(n)=\mathcal{O}(n^{2/3}). For higher dimensions, we show fd(n)=O(ndd+1)f_d(n)=\mathcal{O}\left(n^\frac{d}{d+1}\right), where fd(n)f_d(n) is the largest integer such that every poset on nn elements has a dd-dimensional subposet on fd(n)f_d(n) elements.Comment: removed proof of Theorem 3 duplicating previous work; fixed typos and reference

    Forbidden subposet problems in the grid

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    For posets PP and QQ, extremal and saturation problems about weak and strong PP-free subposets of QQ have been studied mostly in the case QQ is the Boolean poset QnQ_n, the poset of all subsets of an nn-element set ordered by inclusion. In this paper, we study some instances of the problem with QQ being the grid, and its connections to the Boolean case and to the forbidden submatrix problem

    An improvement of the general bound on the largest family of subsets avoiding a subposet

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    Let La(n,P)La(n,P) be the maximum size of a family of subsets of [n]={1,2,...,n}[n]= \{1,2, ..., n \} not containing PP as a (weak) subposet, and let h(P)h(P) be the length of a longest chain in PP. The best known upper bound for La(n,P)La(n,P) in terms of P|P| and h(P)h(P) is due to Chen and Li, who showed that La(n,P)1m+1(P+12(m2+3m2)(h(P)1)1)(nn/2)La(n,P) \le \frac{1}{m+1} \left(|P| + \frac{1}{2}(m^2 +3m-2)(h(P)-1) -1 \right) {\binom {n} {\lfloor n/2 \rfloor}} for any fixed m1m \ge 1. In this paper we show that La(n,P)12k1(P+(3k5)2k2(h(P)1)1)(nn/2)La(n,P) \le \frac{1}{2^{k-1}} (|P| + (3k-5)2^{k-2}(h(P)-1) - 1 ) {n \choose {\lfloor n/2\rfloor} } for any fixed k2k \ge 2, improving the best known upper bound. By choosing kk appropriately, we obtain that La(n,P)=O(h(P)log2(Ph(P)+2))(nn/2)La(n,P) = O\left( h(P) \log_2\left(\frac{|P|}{h(P)}+2\right) \right) {n \choose \lfloor n/2 \rfloor } as a corollary, which we show is best possible for general PP. We also give a different proof of this corollary by using bounds for generalized diamonds. We also show that the Lubell function of a family of subsets of [n][n] not containing PP as an induced subposet is O(nc)O(n^c) for every c>12c>\frac{1}{2}.Comment: Corrected mistakes, improved the writing. Also added a result about the Lubell function with forbidden induced subposets. The final publication will be available at Springer via http://dx.doi.org/10.1007/s11083-016-9390-

    Induced and non-induced forbidden subposet problems

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    The problem of determining the maximum size La(n,P)La(n,P) that a PP-free subposet of the Boolean lattice BnB_n can have, attracted the attention of many researchers, but little is known about the induced version of these problems. In this paper we determine the asymptotic behavior of La(n,P)La^*(n,P), the maximum size that an induced PP-free subposet of the Boolean lattice BnB_n can have for the case when PP is the complete two-level poset Kr,tK_{r,t} or the complete multi-level poset Kr,s1,,sj,tK_{r,s_1,\dots,s_j,t} when all sis_i's either equal 4 or are large enough and satisfy an extra condition. We also show lower and upper bounds for the non-induced problem in the case when PP is the complete three-level poset Kr,s,tK_{r,s,t}. These bounds determine the asymptotics of La(n,Kr,s,t)La(n,K_{r,s,t}) for some values of ss independently of the values of rr and tt

    Supersaturation and stability for forbidden subposet problems

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    We address a supersaturation problem in the context of forbidden subposets. A family F\mathcal{F} of sets is said to contain the poset PP if there is an injection i:PFi:P \rightarrow \mathcal{F} such that pPqp \le_P q implies i(p)i(q)i(p) \subset i (q). The poset on four elements a,b,c,da,b,c,d with a,bc,da,b \le c,d is called butterfly. The maximum size of a family F2[n]\mathcal{F} \subseteq 2^{[n]} that does not contain a butterfly is Σ(n,2)=(nn/2)+(nn/2+1)\Sigma(n,2)=\binom{n}{\lfloor n/2 \rfloor}+\binom{n}{\lfloor n/2 \rfloor+1} as proved by De Bonis, Katona, and Swanepoel. We prove that if F2[n]\mathcal{F} \subseteq 2^{[n]} contains Σ(n,2)+E\Sigma(n,2)+E sets, then it has to contain at least (1o(1))E(n/2+1)(n/22)(1-o(1))E(\lceil n/2 \rceil +1)\binom{\lceil n/2\rceil}{2} copies of the butterfly provided E2n1εE\le 2^{n^{1-\varepsilon}} for some positive ε\varepsilon. We show by a construction that this is asymptotically tight and for small values of EE we show that the minimum number of butterflies contained in F\mathcal{F} is exactly E(n/2+1)(n/22)E(\lceil n/2 \rceil +1)\binom{\lceil n/2\rceil}{2}
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