1,114 research outputs found

    On the greatest common divisor of nn and the nnth Fibonacci number

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    Let A\mathcal{A} be the set of all integers of the form gcd(n,Fn)\gcd(n, F_n), where nn is a positive integer and FnF_n denotes the nnth Fibonacci number. We prove that #(A[1,x])x/logx\#\left(\mathcal{A} \cap [1, x]\right) \gg x / \log x for all x2x \geq 2, and that A\mathcal{A} has zero asymptotic density. Our proofs rely on a recent result of Cubre and Rouse which gives, for each positive integer nn, an explicit formula for the density of primes pp such that nn divides the rank of appearance of pp, that is, the smallest positive integer kk such that pp divides FkF_k

    Conway polynomials of two-bridge links

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    We give necessary conditions for a polynomial to be the Conway polynomial of a two-bridge link. As a consequence, we obtain simple proofs of the classical theorems of Murasugi and Hartley. We give a modulo 2 congruence for links, which implies the classical modulo 2 Murasugi congruence for knots. We also give sharp bounds for the coefficients of the Conway and Alexander polynomials of a two-bridge link. These bounds improve and generalize those of Nakanishi and Suketa.Comment: 15

    SOME CONNECTIONS BETWEEN THE SMARANDACHE FUNCTION AND THE FIBONACCI SEQUENCE

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    This paper is aimed to provide generalizations of the Smarandache function. They will be constructed by means of sequences more general than the sequence of the factorials. Such sequences are monotonously convergent to zero sequences and divisibility sequences (in particular the Fibonacci sequence)

    On the Fürstenberg closure of a class of binary recurrences

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    In this paper, we determine the closure in the full topology over Z of the set {un: n≥0}, where (un)n≥0 is a nondegenerate binary recurrent sequence with integer coefficients whose characteristic roots are quadratic units. This generalizes the result for the case when un=Fn was the nth Fibonacci number

    On perfect powers that are sums of two Fibonacci numbers

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    We study the equation Fn+Fm=ypF_n + F_m = y^p, where FnF_n and FmF_m are respectively the nn-th and mm-th Fibonacci numbers and p2p \ge 2. We find all solutions under the assumption nm(mod2)n \equiv m \pmod{2}.Comment: 6 page
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