135 research outputs found

    A Note on Goldbach Partitions of Large Even Integers

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    Let Σ2n\Sigma_{2n} be the set of all partitions of the even integers from the interval (4,2n],n>2,(4,2n], n>2, into two odd prime parts. We show that Σ2n2n2/log2n\mid\Sigma_{2n}\mid\sim 2n^2/\log^2{n} as nn\to\infty. We also assume that a partition is selected uniformly at random from the set Σ2n\Sigma_{2n}. Let 2Xn(4,2n]2X_n\in (4,2n] be the size of this partition. We prove a limit theorem which establishes that Xn/nX_n/n converges weakly to the maximum of two random variables which are independent copies of a uniformly distributed random variable in the interval (0,1)(0,1). Our method of proof is based on a classical Tauberian theorem due to Hardy, Littlewood and Karamata. We also show that the same asymptotic approach can be applied to partitions of integers into an arbitrary and fixed number of odd prime partsComment: 8 page

    Every sufficiently large even number is the sum of two primes

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    The binary Goldbach conjecture asserts that every even integer greater than 44 is the sum of two primes. In this paper, we prove that there exists an integer KαK_\alpha such that every even integer x>pk2x > p_k^2 can be expressed as the sum of two primes, where pkp_k is the kkth prime number and k>Kαk > K_\alpha. To prove this statement, we begin by introducing a type of double sieve of Eratosthenes as follows. Given a positive even integer x>4x > 4, we sift from [1,x][1, x] all those elements that are congruents to 00 modulo pp or congruents to xx modulo pp, where pp is a prime less than x\sqrt{x}. Therefore, any integer in the interval [x,x][\sqrt{x}, x] that remains unsifted is a prime qq for which either xq=1x-q = 1 or xqx-q is also a prime. Then, we introduce a new way of formulating a sieve, which we call the sequence of kk-tuples of remainders. By means of this tool, we prove that there exists an integer Kα>5K_\alpha > 5 such that pk/2p_k / 2 is a lower bound for the sifting function of this sieve, for every even number xx that satisfies pk2<x<pk+12p_k^2 < x < p_{k+1}^2, where k>Kαk > K_\alpha, which implies that x>pk2  (k>Kα)x > p_k^2 \; (k > K_\alpha) can be expressed as the sum of two primes.Comment: 32 pages. The manuscript was edited for proper English language by one editor at American Journal Experts (Certificate Verification Key: C0C3-5251-4504-E14D-BE84). However, afterwards some changes have been made in sections 1, 6, 7 and
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