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k 2 ) 2 u 1 = (1 \Gamma 3jAj 2 )A exp(ikx): (1) Restricting secular solutions of Eq.(1) to the following form u 1 = P (t; x; y)(1 \Gamma 3jAj 2 )A exp(ikx); 1 where P is a polynomial of t; x and y, we rewrite Eq.(1) as LP = 1; (2) where !! L j @ t + (@ 2 x + @ 2 y + 2ik@ x ) 2 : (3) In addition to previously known polynomial solutions of Eq.(2) [2]: P 1 = t; P 2 = \Gamm

Year: 1997

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