Skip to main content
Article thumbnail
Location of Repository

Ek+1 ≈ CE (1+ √ 5)/2 k



The convergence of the secant method is superlinear The purpose of this document is to show the following theorem: Theorem 1.1 Let {xk} ∞ k be the sequence produced by the secant method. Assume the sequence converges to a root of f(x) = 0, i.e., xk → x∞, f(x∞) = 0. Moreover, assume the root x ∞ is regular: f ′(x∞) ̸ = 0. Denote the error in the kth step by Ek = xk − x∞. Under these assumptions, we have The theorem is implied by three lemmas

Year: 2011
OAI identifier: oai:CiteSeerX.psu:
Provided by: CiteSeerX
Download PDF:
Sorry, we are unable to provide the full text but you may find it at the following location(s):
  • (external link)
  • (external link)
  • Suggested articles

    To submit an update or takedown request for this paper, please submit an Update/Correction/Removal Request.